What three numbers have an average of 402?

Part 1: Understanding the Problem

We're looking for three numbers whose average is 402. This means if we add these three numbers together and divide by 3, we should get 402.

Step-by-step Solution:

  1. Recall the average formula: Average = (Sum of numbers) / (Count of numbers)
  2. In this case: 402 = (x + y + z) / 3
  3. To find the sum, multiply both sides by 3: 402 * 3 = x + y + z
  4. So, the sum of our three numbers should be: 1206

Part 2: Finding Solutions

Now, let's find multiple sets of three numbers that add up to 1206.

Solution 1:

402, 402, 402

Verification:

(402 + 402 + 402) / 3 = 1206 / 3 ≈ 402

This solution is correct!

Solution 2:

402, 402, 402

Verification:

(402 + 402 + 402) / 3 = 1206 / 3 ≈ 402

This solution is correct!

Solution 3:

174, 369, 663

Verification:

(174 + 369 + 663) / 3 = 1206 / 3 ≈ 402

This solution is correct!

Solution 4:

315, 169, 722

Verification:

(315 + 169 + 722) / 3 = 1206 / 3 ≈ 402

This solution is correct!

Solution 5:

584, 491, 131

Verification:

(584 + 491 + 131) / 3 = 1206 / 3 ≈ 402

This solution is correct!

Explanation:

As you can see, there are many possible solutions. We can find more by:

Remember:

Try it out:

(X+Y+Z) / 3 = 735What three numbers have an average of 735 ?
(X+Y+Z) / 3 = 612What three numbers have an average of 612 ?
(X+Y+Z) / 3 = 521What three numbers have an average of 521 ?

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