What three numbers have an average of 712?

Part 1: Understanding the Problem

We're looking for three numbers whose average is 712. This means if we add these three numbers together and divide by 3, we should get 712.

Step-by-step Solution:

  1. Recall the average formula: Average = (Sum of numbers) / (Count of numbers)
  2. In this case: 712 = (x + y + z) / 3
  3. To find the sum, multiply both sides by 3: 712 * 3 = x + y + z
  4. So, the sum of our three numbers should be: 2136

Part 2: Finding Solutions

Now, let's find multiple sets of three numbers that add up to 2136.

Solution 1:

712, 712, 712

Verification:

(712 + 712 + 712) / 3 = 2136 / 3 ≈ 712

This solution is correct!

Solution 2:

712, 712, 712

Verification:

(712 + 712 + 712) / 3 = 2136 / 3 ≈ 712

This solution is correct!

Solution 3:

2051, 23, 62

Verification:

(2051 + 23 + 62) / 3 = 2136 / 3 ≈ 712

This solution is correct!

Solution 4:

1787, 52, 297

Verification:

(1787 + 52 + 297) / 3 = 2136 / 3 ≈ 712

This solution is correct!

Solution 5:

248, 630, 1258

Verification:

(248 + 630 + 1258) / 3 = 2136 / 3 ≈ 712

This solution is correct!

Explanation:

As you can see, there are many possible solutions. We can find more by:

Remember:

Try it out:

(X+Y+Z) / 3 = 869What three numbers have an average of 869 ?
(X+Y+Z) / 3 = 418What three numbers have an average of 418 ?
(X+Y+Z) / 3 = 435What three numbers have an average of 435 ?

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